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Activity needed

August 17, 2025/in General Questions /by Besttutor

1. What mass of NaOH(s) must be added to 300 mL of HCl 0.25 M in order to completely neutralize this acid?

2. During a lab, you mix 2 solutions: a 100 ml solution containing 0.40 g of NaOH and a 100 mL solution containing 0.73 g of HCl. What is the concentration of H+ ions in the new solution?

3. Calculate the [H+] of a solution obtained by mixing 1 L of hydrochloric acid 1.0 M with 1 litre of sodium hydroxide 0.990 M.

4. In order to completely neutralize 20 mL of a solution of HCl 0.1 M, 40 mL of a solution of NaOH must be added. What is the concentration (in M) of the NaOH solution?

5. 25 mL of NaOH 0.16 M is added to 50 mL of 0.1 M HCl.

6. What is the pH of the final solution?

7. What is the concentration of hydroxide ions in the solution?

8. Calculate the volume of Ba(OH)2 0.20 M necessary to neutralize 300.0 mL of H3PO4 0.30 M.

9. During an acid-base titration, 23.3 mL of HCl completely neutralized 19.5 mL of potassium hydroxide 0.315 M. Calculate the concentration of the hydrochloric acid.

10. What is the pH at the equivalence point during an acid-base titration of NaOH and HCl, having identical molarities? Justify

11. During an acid-base titration, 25 mL of NaOH 0.2 M were required to neutralize 20 mL of HCl.

Calculate the pH of the solution for each of the following:

12. Before the titration.

13. After adding 24.9 mL of NaOH.

14. At the equivalence point.

15. After adding 25.1 mL of NaOH.

16. The pH of the equivalence point during a certain titration is 3.5.

17. Which indicator would be adequate for this titration?

18. Which indicator would you suggest to be avoided during this titration? Justify.

19. Calculate the volume of NaOH 0.5 mol/L necessary to neutralize 300 mL of HCl 0.2 M.

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chemistry 111

August 17, 2025/in General Questions /by Besttutor

chemistry 111

This is the first assignment for Chem 111.  These problems are all from chapter 1, Please turn the assignment in on regular notebook paper, Keep in mind, for full credit. The assignment is worth 25 points and is graded on completion.  You must show your work and have appropriate units for all questions.

 

 

Chapter 1 Problems: 16, 18, 19, 20, 24, 26, 28, 34, 38, 44, 48, 60, 94

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Chemistry homework help

August 17, 2025/in General Questions /by Besttutor

A substance that has a definite shape, a crystalline structure, and a definite volume at STP is

A) F2

B) Cl2

C)Br2

D) I2

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Formal chemistry Lab

August 17, 2025/in General Questions /by Besttutor

CHM 2045L- Equivalent Mass of an Acid

 

1

Equivalent Mass of an Acid

Objectives: Upon successful completion of this laboratory the student will be able to:

1) Perform an acid-base titration accurately to an indicator endpoint.

2) Calculate moles from molarity and volume.

3) Write the complete, and net ionic equation for the neutralization of an acid with a base.

4) Calculate equivalent mass from total mass and moles of hydronium ion.

5) Write a formal scientific communication (laboratory report).

Introduction: Titration is a simple and very frequently used technique of quantitative volumetric

analysis, which is able to achieve great precision and accuracy when it is done properly. The titration

apparatus is shown in Figure 1. It consists of a Burette (A), a clamp (B), a stand (C) and a container (D)

in which the titration reaction occurs. The Burette has a valve (E) that allows precise control of the flow

of liquid from the burette, and it has a thin tip (F) that produces small and very uniform drops.

 

Figure 1, Titration Apparatus

There is a solution that has a very precisely known concentration of one of the reactants in the Burette.

This is called the titrant. The flask has an unknown amount of the other reactant, called the analyte. The

analyte can be a known volume of a solution of unknown concentration, or it can be a carefully weighed

 

http://chemwiki.ucdavis.edu/Analytical_Chemistry/Quantitative_Analysis/Titration/Acid-Base_Titrations
https://www.google.com/#safe=off&q=analyte

 

CHM 2045L- Equivalent Mass of an Acid

 

2

solid compound or mixture dissolved in a solvent. In this lab you will titrate a solid that you have

weighed to the nearest 1 mg and then dissolved in water.

Notice that the burette is marked the opposite way that a graduated cylinder is marked. It has the 0 mark

at the top and the 50 mark at the bottom. Rather than being how much the burette contains, these marks

represent how much has been removed from the burette, if the level starts at exactly 0.00 ml. What if you

start titrating at some number other than 0? Then simply subtract your initial measurement from the final

measurement.

When you are reading a burette, just as with any other instrument, your measurement precision should go

1 decimal place past the smallest tic mark (Figure 2)

 

Figure 2 How to read a burette

The smallest tic mark on our burettes is 0.1 ml. This means that you will read the burettes to the nearest

0.01 ml.

 

 

 

CHM 2045L- Equivalent Mass of an Acid

 

3

The number of moles of analyte present can be determined easily from the volume of the titrant, the

concentration of the titrant in 𝑚𝑜𝑙𝑒𝑠

𝑙𝑖𝑡𝑒𝑟 (molarity, also abbreviated as M), and the balanced equation of the

reaction between the titrant and the analyte. This can tell you a number of things. If you know the

formula and molar mass of the analyte, it can tell you how many grams are present, and the percent

composition of a carefully weighed sample of the analyte material. If the volume of the analyte solution

is known precisely, it can tell you the molar concentration of the analyte solution, and if you know the

mass of a pure unknown compound, it can tell you the molar mass, of that compound.

The equation to obtain the moles of analyte from the volume of titrant is as follows:

𝑉 𝑡𝑖𝑡𝑟𝑎𝑛𝑡 (𝑚𝑙) × 1𝐿

1000𝑚𝑙 × 𝑚𝑜𝑙𝑒𝑠 𝑡𝑖𝑡𝑟𝑎𝑛𝑡

1 𝐿 𝑡𝑖𝑡𝑟𝑎𝑛𝑡 × 𝑚𝑜𝑙𝑒𝑠 𝑎𝑛𝑎𝑙𝑦𝑡𝑒

𝑚𝑜𝑙𝑒𝑠 𝑡𝑖𝑡𝑟𝑎𝑛𝑡 = 𝑚𝑜𝑙𝑒𝑠 𝑎𝑛𝑎𝑙𝑦𝑡𝑒

Equation 1 calculation of moles of analyte

To find the mass, multiply by molar mass

𝑚𝑜𝑙𝑒𝑠 𝑎𝑛𝑎𝑙𝑦𝑡𝑒 × 𝑔𝑟𝑎𝑚𝑠 𝑎𝑛𝑎𝑙𝑦𝑡𝑒

1 𝑚𝑜𝑙𝑒 𝑎𝑛𝑎𝑙𝑦𝑡𝑒 = 𝑔𝑟𝑎𝑚𝑠 𝑎𝑛𝑎𝑙𝑦𝑡𝑒

Equation 2, calculation of mass of analyte

To find percent composition, divide by total grams mixture:

𝑔𝑟𝑎𝑚𝑠 𝑎𝑛𝑎𝑙𝑦𝑡𝑒

𝑔𝑟𝑎𝑚𝑠 𝑚𝑖𝑥𝑡𝑢𝑟𝑒 × 100% = 𝑝𝑒𝑟𝑐𝑒𝑛𝑡 𝑎𝑛𝑎𝑙𝑦𝑡𝑒

Equation 3, Calculation of percent composition of an analyte mixture

To find the molar mass of an analyte divide the mass of the analyte by the moles of analyte

𝑔𝑟𝑎𝑚𝑠 𝑎𝑛𝑎𝑙𝑦𝑡𝑒

𝑚𝑜𝑙𝑒𝑠 𝑎𝑛𝑎𝑙𝑦𝑡𝑒 = 𝑔𝑟𝑎𝑚𝑠

1 𝑚𝑜𝑙𝑒 𝑎𝑛𝑎𝑙𝑦𝑡𝑒⁄

Equation 4 calculation af the molar mass of an analyte

Understanding the experiment: In this experiment we will perform an acid – base neutralization reaction,

and use equations 1 and 4 to find the equivalent mass of an acid. Acids are broadly defined as sources of

hydrogen ions, H+, also called protons. In water, acids will react with water to form hydronium ions,

H3O+, by the following reaction, where HA stand for a generic acid. This reaction is also called acid

dissociation.

𝐻𝐴 + 𝐻2𝑂 → 𝐻3𝑂 + + 𝐴−

Equation 5 dissociation of a monoprotic acid in water

In fact, the proton, or H+ ion, never exists alone in a water solution. It always exists as the hydronium

ion, H3O+. Often people will talk about the hydrogen ion and refer to it as H+, but what they really mean is

hydronium ion.

Acids can be mono-protic, di-protic, tri-protic and even poly-protic, depending on how many hydrogen

ions they can donate. The stoichiometric ratio of a mono-protic acid is 1 to 1; that of a diprotic acid is 1

to 2; that of a triprotic acid is 1 to 3 and so forth. The reaction of a strong di-protic acid with water would

be:

 

 

 

CHM 2045L- Equivalent Mass of an Acid

 

4

 

𝐻2𝐴 + 2 𝐻2𝑂 → 2𝐻3𝑂 + + 𝐴2−

Equation 6, Dissociation of a diprotic acid in water

Notice the stoichiometric ratio of hydronium ion to acid is 2 to 1. The equivalent mass of the acid is the

amount required to produce 1 mole of hydronium ion. It would take half as many moles of the acid in

equation 2 to make a mole of hydronium ion as it would if it were a monoprotic acid.

From this, you can see that the equivalent mass of a monoprotic acid will be equal to its molar mass,

while the equivalent mass of a diprotic acid will be ½ of its molar mass. For a triprotic acid it would be

1/3 and so forth. Examples of monoprotic, diprotic and triprotic organic acids are shown in Figure 3. The

acidic proton is shown in bold.

 

Figure 3 Organic acid structures.

A base is broadly defined as a compound that absorbs hydrogen ions. Bases produce hydroxide ions, OH-

, in water in one of two ways. They either dissociate in water to form hydroxide ions (These are called

Arrhenius bases), or they react with water to produce hydroxide ions. The base that we will use in this

laboratory, sodium hydroxide, is one of the ones that dissociates in water. The equation is below.

𝑁𝑎𝑂𝐻(𝑠) 𝐻2𝑂 → 𝑂𝐻− (𝑎𝑞) + 𝑁𝑎+(𝑎𝑞)

Equation 7, Dissociation of an Arrhenius base in water

Observe that sodium hydroxide will produce exactly as many moles of hydroxide ion as there are moles

of sodium hydroxide that dissolve. Ammonia is an example of a base that react with water to form

hydroxide ion. These bases are called Brønsted-Lowry bases. The equation for the reaction of ammonia

is shown below:

𝑁𝐻3 + 𝐻2𝑂 → 𝑂𝐻 − + 𝑁𝐻4

+ Equation 8, Dissociation of a Brønsted Lowry base in water

A major simplification that is being made in this description of acids and bases is the assumption that they

dissociate or react completely with the water to form hydroxide or hydronium ions. While this is true of

strong acids and bases, there are many weak acids and bases that only react a little bit before the reaction

starts going in the other direction to establish what is called an equilibrium with only a very low

concentration of hydronium or hydroxide ion. A complete description of weak acids and weak bases is

beyond the scope of this course. You will study this and other aspects of equilibrium in grueling detail, in

CHM 2046. No worries, though; you will have a whole lot more chemistry under your belt by then.

Even though all of the acids that will be used in this laboratory are considered weak acids, they will

completely dissociate through the course of the titration, because the sodium hydroxide is a strong base,

and it will completely react with the small amount of hydronium produced by any aqueous acid, no matter

 

http://chem-guide.blogspot.com/2010/03/concept-of-equivalent-mass.html
http://chemwiki.ucdavis.edu/Physical_Chemistry/Acids_and_Bases/Acid/Arrhenius_Concept_of_Acids_and_Bases
http://chemwiki.ucdavis.edu/Physical_Chemistry/Acids_and_Bases/Acid/Bronsted_Concept_of_Acids_and_Bases
http://www.chem1.com/acad/webtext/chemeq/

 

CHM 2045L- Equivalent Mass of an Acid

 

5

how weak it is. This will drive more of the acid to dissociate and make more hydronium ion, which will

in turn be gobbled up by the hydroxide ion, until there is no acid left. This tendency is known as Le

Chatelier’s principle. It is also a topic that will be covered extensively in CHM 2046.

The equations of acid and base add together as follows

𝐻𝐴 (𝑎𝑞) + 𝐻2𝑂(𝑙) → 𝐻3𝑂 +(𝑎𝑞) + 𝐴−(𝑎𝑞)

+

𝑁𝑎𝑂𝐻(𝑠) 𝐻2𝑂 → 𝑂𝐻− (𝑎𝑞) + 𝑁𝑎+(𝑎𝑞)

+

𝐻3𝑂 + + 𝑂𝐻− → 2𝐻2𝑂(𝑙)

=

𝑁𝑎𝑂𝐻(𝑠) + 𝐻𝐴 (𝑎𝑞) 𝐻2𝑂 → 𝐻2𝑂(𝑙) + 𝑁𝑎

+(𝑎𝑞) + 𝐴−(𝑎𝑞) scheme 1, Reaction of an acid and a base

The third equation is called the net ionic equation for acid base neutralization. It can be derived by

assuming that the acid and the base are present in their completely dissociated forms.

𝐻3𝑂 +(𝑎𝑞) + 𝐴−(𝑎𝑞) + 𝑂𝐻− (𝑎𝑞) + 𝑁𝑎+(𝑎𝑞)

𝐻2𝑂 → 𝐻2𝑂(𝑙) + 𝑁𝑎

+(𝑎𝑞) + 𝐴−(𝑎𝑞) Equation 9, Total ionic equation of an acid base reaction

The ions that are crossed out are called spectator ions, because they appear on both sides of the arrow.

Taking them out gives you the third equation in scheme 1.

You can Also see that the stoichiometric ratio for a dibasic acid is two to one, base to acid, and for a

tribasic acid the stoichiometric ratio of base to acid is 3 to 1, as shown in equations 10 and 11.

2𝑁𝑎𝑂𝐻(𝑠) + 𝐻2𝐴 (𝑎𝑞) 𝐻2𝑂 → 2𝐻2𝑂(𝑙) + 2𝑁𝑎

+(𝑎𝑞) + 𝐴2−(𝑎𝑞) Equation 10 Reaction of a diprotic acid with sodium hydroxide

3𝑁𝑎𝑂𝐻(𝑠) + 𝐻3𝐴 (𝑎𝑞) 𝐻2𝑂 → 3𝐻2𝑂(𝑙) + 2𝑁𝑎

+(𝑎𝑞) + 𝐴3−(𝑎𝑞) Equation 11, reaction of a triprotic acid with sodium hydroxide

Because 1 mole sodium hydroxide reacts with 1 mole hydronium ion, the equivalent mass of the acid is

the mass of the acid divided by the moles of sodium hydroxide. In other words:

𝐸𝑞𝑢𝑖𝑣𝑎𝑙𝑒𝑛𝑡 𝑚𝑎𝑠𝑠( 𝑔 𝑚𝑜𝑙⁄ ) =

𝑀𝑎𝑠𝑠 𝑎𝑐𝑖𝑑 (𝑔)

𝑚𝑙 𝑁𝑎𝑂𝐻 × 1000𝑚𝑙

1 𝐿 ×

1

𝑚𝑜𝑙𝑒𝑠 𝐿⁄ 𝑠𝑜𝑑𝑖𝑢𝑚 ℎ𝑦𝑑𝑟𝑜𝑥𝑖𝑑𝑒

 

In most cases, both reactants and products of acid base reactions are colorless. It would therefore be

impossible to see when the reaction is complete. To determine this we need to add an indicator dye.

Indicator dyes are dyes that react with something in the reaction mixture to change color when the

reaction is done. We will use dye molecule called phenolphthalein, which is a very weak acid that is

much less likely to give up its protons than the acids that we are titrating. When phenolphthalein does

give up its protons, it turns pink, or red. When the very last molecule of the acid reacts, there is no more

hydronium ion to react. This is called the equivalence point. When the equivalence point is reached, the

hydroxide ion in the next drop of titrant will react with the phenolphthalein and turn it red.

 

https://www.khanacademy.org/science/chemistry/chemical-equilibrium/factors-that-affect-chemical-equilibrium/v/le-chatelier-s-principle
https://www.khanacademy.org/science/chemistry/chemical-equilibrium/factors-that-affect-chemical-equilibrium/v/le-chatelier-s-principle
http://chemwiki.ucdavis.edu/Physical_Chemistry/Acids_and_Bases/Case_Studies/Acid_and_Base_Indicators
https://en.wikipedia.org/wiki/Phenolphthalein
https://en.wikipedia.org/wiki/Equivalence_point

 

CHM 2045L- Equivalent Mass of an Acid

 

6

 

Figure 4 structure of phenolphthalein acidic hydrogens are shown in bold

This marks the endpoint of the titration. At the true end point, very little phenolphthalein will have

reacted, so your solution will be a very light pink. If it turns dark pink, you will have added too much

base. See Figure 5. The flask on the left is a perfect endpoint. The one on the right has too much base

added.

 

Figure 5, Good endpoint (left) overshot endpoint(right)

It is important to continuously swirl your analyte solution. If you do not, you can get a false endpoint.

The color will appear, but then disappear when you stir it. As you approach the endpoint clouds of pink

color will appear briefly when you add the base, then disappear (figure 6).

 

Figure 6, transient pink cloud near endpoint

 

 

 

CHM 2045L- Equivalent Mass of an Acid

 

7

Procedure:

1) Obtain a vial of unknown acid from the chemical stockroom.

2) Obtain the following equipment: burette clamp, ring stand, Burette with valve and tip, burette funnel, 3

clean 250ml Erlenmeyer flasks, a 250 ml beaker, 2 or 3 little squares of white paper, a squirt bottle, and

a few plastic transfer pipettes. Make sure that the valve fits snugly in the burette and that the tip fits

snugly in the valve.

3) Wash out the squirt bottle with deionized water and fill it with deionized water. Then wash the burette,

two of the three flasks and the beaker with deionized water. Dry the beaker with a clean paper towel.

4) Dispense about 150 ml of the sodium hydroxide solution from the carboy into the beaker. Write down

the molar concentration of this solution.

Caution! Sodium hydroxide is very caustic and it will permanently blind you if it gets in your

eyes, even in low concentrations. Wear approved Safety glasses or goggles!

5) Assemble the burette in the burette clamp, and use a transfer pipette to run a few pipettes full of the

sodium hydroxide solution down the inside walls of the burette. Put the unwashed Erlenmeyer flask

under the burette, and drain out the sodium hydroxide solution into the Erlenmeyer flask. Repeat this

process 2 more times.

6) Place the funnel in the top of the burette and carefully pour the sodium hydroxide until it reaches close to

the 0.00 ml mark.

7) Open the valve and let a few drops of the sodium hydroxide titrant run into the waste flask. This will fill

the tip of the burette with titrant.

8) Discard the waste solution in the sink and wash the flask thoroughly with deionized water.

9) Take the unknown sample of acid to the balance. Put a plastic weigh boat onto the balance and press

“tare”. When the balance reads 0.000g, weigh out the amount of unknown acid that is indicated on the

vial to the nearest 0.001g. Do not exceed this amount, or you might not be able to titrate it with only 1

burette full of sodium hydroxide solution. Write the mass down on your data sheet.

10) Carefully pour the acid powder into one of the flasks. Use the corner of the weigh boat to pour from.

With your squirt bottle, wash any solid that remains on the weigh boat into the flask. Mark this flask

“rough”

11) Put about 50 ml of deionized water into the flask and then swirl the flask to dissolve as much of the acid

as possible. Add a few drops of phenolphthalein solution to the flask.

12) Use a ruler or the edge of a notebook as a straight edge, and draw a thick dark line horizontally across

one of the small pieces of white paper. Place the other piece under the burette, and place the flask with

the acid solution on top of it.

13) Hold the paper with the line behind the burette, so that the line is horizontal, just underneath the

meniscus. This will reflect off of the meniscus, making it easier to read (see Figure 7). With your eye at

the level of the meniscus, read the burette to the nearest 0.01 ml.

14) While constantly swirling the flask of analyte, open the valve and rapidly titrate until the acid solution

turns pink. Be ready to stop the flow when the color change occurs.

15) Write the initial volume, final volume and net volume (final – initial) in the “rough” section of the data

sheet.

16) Refill the burette with sodium hydroxide solution and let a little run through the pipette tip into the

titrated sample if it is necessary to refill the tip of the burette.

17) Repeat steps 9 through 11 with the other two flasks. Mark them “trial 1” and “trial 2”.

 

 

 

CHM 2045L- Equivalent Mass of an Acid

 

8

18) To help you to estimate the amount of titrant that will be needed for trials 1 and 2, you can do a

proportional calculation as shown below. This will allow you to titrate quickly to just under the

estimated volume, and then titrate slowly to get an accurate endpoint.

𝑒𝑠𝑡𝑖𝑚𝑎𝑡𝑒𝑑 𝑡𝑟𝑖𝑎𝑙 𝑛𝑒𝑡 𝑣𝑜𝑙𝑢𝑚𝑒 = 𝑟𝑜𝑢𝑔ℎ 𝑛𝑒𝑡 𝑣𝑜𝑙𝑢𝑚𝑒

𝑟𝑜𝑢𝑔ℎ 𝑎𝑐𝑖𝑑 𝑚𝑎𝑠𝑠 × 𝑡𝑟𝑖𝑎𝑙 𝑎𝑐𝑖𝑑 𝑚𝑎𝑠𝑠

19) Read the initial volume as in step 13, and add the estimated net volume for Trial 1 to the initial volume

to get the estimated final volume.

20) Titrate rapidly to about 5 ml before the estimated final volume for Trial 1. Then titrate the solution drop

by drop, with constant swirling until it turns a very light pink.

21) Measure the final volume as in step 13, and write down the measured initial volume and final volume in

the “Trial 1” column of your data sheet.

22) Refill the burette and repeat steps 19 through 21 for trial 2.

23) Calculate the equivalent mass of the acid for trials 1 and 2, then calculate the average value.

24) Discard the titrated acid solutions and the excess sodium hydroxide solution in the sink with water.

Clean and return all the equipment. Return the acid sample to the stockroom, and clean up your work

area.

 

 

Figure 7, reading the meniscus with a black line

 

 

 

CHM 2045L- Equivalent Mass of an Acid

 

9

Report Sheet: Equivalent Mass of an Acid

Name: ___________________________________________________________________________

Lab Partner(s):_____________________________________________________________________

Class period: ______________________________________ Date: __________________

Data sheet: to be turned in only with full, formal lab report.

Unknown number

 

NaOH molarity

Rough: used to estimate endpoint for titrations in trials 1 and 2

Acid Mass Initial Volume Final Volume Net Volume

 

 

Trial 1 Trial 2

Acid mass (g)

Estimate the net volume

needed for this mass of acid

based on the rough

 

 

 

Your Initial volume (ml)

What is your estimated final

volume (ml)

 

 

 

Your Measured final

volume (ml)

 

Your Measured net volume

(ml)

 

Measured net volume (L)

 

 

 

Moles OH─

 

 

 

Moles H3O+

 

 

 

Equivalent mass

of acid (g/mol)

 

 

 

 

Average equivalent mass ____________________

 

 

CHM 2045L- Equivalent Mass of an Acid

 

10

Prelab: Equivalent Mass of an Acid

Name: ___________________________________________________________________________

Class period: ______________________________________ Date: __________________

Show calculations and be mindful of significant figures for full credit.

The following data were observed in an equivalent mass of an acid experiment.

1) Fill in the blanks (2 points each). Show all calculations for full credit.

NaOH molarity Acid mass Initial volume

(ml)

Final volume

(ml)

Net volume

(ml)

0.1000 M 0.2511g

 

 

Numerical value:

 

2) (3 points) How many moles of hydroxide ion were consumed in the titration?_________________

 

 

3) (3 points) How many moles of hydronium ion were available from the acid?___________________

 

 

4) (4 points) What is the equivalent molar mass of the acid? ____________

 

 

5) (4 points) If it happened that the acid in this experiment was one of the ones represented

in the table below, what is the most likely identity of this acid? ___________________

 

Acid name Molar mass Number of protons

Butanoic acid 88.11 g/mol 1

Tartaric acid 150.087 g/mol 2

Citric acid 192.124 g/mol 3

 

 

 

 

CHM 2045L- Equivalent Mass of an Acid

 

11

Formal Laboratory Report

This lab requires a formal laboratory report that will be turned in online through Turnitin. Specific

guidelines for writing the report are shown below:

Section Requirements

Introduction

(10 points)  Explain the objective of the experiment and describe how the stoichiometry of the

acid base reaction can be used to volumetrically determine the equivalent mass of

the acid.

 Provide an example of how titration is used in medicine, industry, or environmental protection.

 Write in passive voice for example: “The volume and concentration of the base solution are used to find the number of moles of acid present.” not “I will use the

volume and concentration of the base solution to find the number of moles of acid

present.”

 Cite any references with sufficient detail that your instructor can find them.

Procedure

(20 points)  Write the procedure in your own words. Do not copy the procedure in the lab

manual

 The procedure should contain sufficient detail that a chemist of equal experience can duplicate the experiment

 Use passive voice past tense. For example: “The burette was filled to 1 cm above the 0 ml mark with a 0.097 M sodium hydroxide solution.” not “Fill the burette to

1 cm above the 0 ml mark with a 0.097 M sodium hydroxide solution.”

 Cite any references

Data and

calculation

(60 points)

 All quantitative results should be presented as tables or graphs, and also described in paragraph form.

 Volumes should be recorded to the 0.01 ml place, and masses should be recorded to within 0.001g.

 Use Passive voice past tense

 Show the calculations for net volume, moles base, moles acid, and equivalent mass of the acid.

 

Results and

discussion

(30 points)

 List the values obtained for the equivalent mass of the acid for all titrations, and the average values.

 Compare the values of each titration to each other, and evaluate how closely they agree.

 Discuss whether or not your results are reasonable. The highest equivalent masses in this experiment are about 200 g/mol, and the lowest equivalent mass organic

acid is oxalic acid, with an equivalent mass of 45 g/mol. Anything much less than

this is probably not reasonable, and masses of more than 500 are also not

reasonable in this experiment.

 Use passive voice in this section as well.

Conclusion

(10 points)  Discuss any experimental factors that could influence the reliability of your results

 Given the equipment provided and your evaluation of the results of this experiment, discuss whether or not you could perform the titration in the practical

example that you provided in the introduction with sufficient precision and

accuracy

Prelab

(20 points)

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Chemistry Discussion Questions

August 17, 2025/in General Questions /by Besttutor

Chemistry Discussion Question and classmates response:

DQ2 must be 2 paragraphs and classmates response must be 1 paragraph. Must be you own work.

DQ2

Define the terms theoretical, actual, and percentage yield. Why is the percentage yield always less than the theoretical yield? Give a specific example. You need to respond to my questions and to at least three classmates substantially over three days in a manner that furthers the discussion.  Some ideas for responses:             1. Add information that your classmate didn’t include in his/her post.             2. Respond to a classmate’s example.             3. Make up a similar example using a classmate’s information.

 

 

Classmate’s responses:

1. The theoretical yield of product is “the maximum amount of product that can be obtained by a reaction from given amounts of reactant” (Ebbing & Gammon, 2012, p.94). Actual yield of the amount actually produced of a product, and percentage yield is “the actual yield expressed as a percentage of the theoretical yield” (Ebbing & Gammon, 2012, p. 95).

There are several reasons why the actual yield is always less than the theoretical yield and here are some reasons, impure reactants and competing side reactions, products can be lost during processes, miscalculations in measurement, and reactions do not always go through completion. An example, is nitrobenzene (C6H5NO2), start with 15.6g of benzene (c6H6), in excess of nitric acid (HNO3). However, is all C6H6 was converted to product, in theory we should obtain 24.6g of product, which would be 100% yield. If 18.0g was isolated, we could then calculate the percent yield: 18.0g/24.6g*100 = 73.2%. So this would make the percentage yield less than the theoretical yield.

2. Theoretical yield is the maximum quantity of a product that can be formed in a chemical reaction if all the limiting reactant reacted to form products. Actual yield is an amount of a specified pure product obtained from a given reaction. Percentage yield is getting the efficiency of a reaction. There are a few reasons the percentage yield is always that the theoretical yield. One reason is part of the reactants may not react, or they may react in a way different from that desired (side reactions). In addition, it is not always possible to recover all of the reaction product from the reaction mixture.

An example of this is the reaction of rust to iron. The theoretical yield is 699.5 grams of iron; my actual yield is 525.0 grams. Therefore, the precent yield is

%yield= 525.0 g/699.5 g x100= 75.05%

A percent yield of about 75 percent isn’t too bad, but chemist and chemical engineers would rather see 90+ percent.

3. The theoretical yield: is the max amount of product that can be obtained in a chemical reaction. This is calculated from the limiting reagent. This can be obtained only under perfect conditions if no product is lost in the process.The actual yield :is the amount of product actually obtained from a chemical reaction. This must be experimentally determined; it can not be calculated. This amount is never more than the theoretical yield. And also can never be 100% due to limitations. Percent yield: is defined as the actual yield/ theoretical yield * 100%Example: if 16.0g of CaCO3 are decomposed and 7.54g of CaO are obtained, what is the % yield of CaO obtained? Equation: CaCO3 > CaO + CO2 (balanced equation)

step 1) make sure that you have a balanced equation

step 2) calculate theoretical yield: (must convert in moles)

16g CoCO3* (1 mol CaCO3/100.1g CaCO3(molar mass)) * (1mol CaO/1mol CaCO3) * (56.1g CaO (molar mass)/1 mol    CaO=8.97g of CaO (theoretical yield)

step 3) calculate percentage yield: 7.54g (actual yield)/8.97g(theoretical yield)* 100%=84.1%

Actual yield is less than the theoretical yield for a few reasons: there may be competing reactions which hinder the process under consideration; external conditions may not be perfectly maintained; reactants may not be perfect

 

 

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Chemistry Discussion Questions

August 17, 2025/in General Questions /by Besttutor

Chemistry Discussion Question and classmates response:

DQ1 must be 2 paragraphs and classmates response must be 1 paragraph. Must be you own work.

DQ1

What is the significance of a limiting reactant. Discuss how it is found and what it tells us about the amount of product that can be formed. Give a specific example. You need to respond to my questions and to at least three classmates substantially over three days in a manner that furthers the discussion.  Some ideas for responses:             1. Add information that your classmate didn’t include in his/her post.             2. Respond to a classmate’s example.             3. Make up a similar example using a classmate’s information.

 

Classmate’s responses:

1. The limiting reactant is the reactant that is entirely consumed when a reaction goes to completion” (Ebbing & Gammon, 2013, p. 90). Limited reactant is also known as limiting reagent. The way you would find limited reactant is by looking at the number of moles in each reactant. First, you would determine the balanced chemical equation, second you would convert all information into moles, and last you would calculate the mole ratio for the information that is given to you. You must first identify the order of the limited reactant because you could calculate the percentage yield. With that being said, the reactant in a chemical reaction limits the amount of product that can be formed and this is also known as the limiting reactant. How to identify what reactant is a limited reactant, for example, if you have 1 mole of hydrogen and one mole of oxygen then the limited reactant will be hydrogen. This is due to the balanced equation for making water, we can see that it takes twice as many moles of hydrogen atoms than oxygen atoms to make up water. Furthermore, each oxygen atom requires 2 hydrogen atoms in order to make up water. The hydrogen would run out before oxygen does, and once this happens, the reactant would have to come to an end.

2. The limiting reactant is the reactant that controls the amount of product possible for a process because once the limiting reactant has been consumed, no further reaction can occur. So, the limiting reactant is very important in chemical reactions because it limits the amount of product that can be formed. The reaction will come to an end when all the limiting reactant is consumed. We can calculate the limiting reactant in this way: 1) make sure you have a balanced chemical equation for the chemical reaction 2)convert all given information to moles ( can be done using molar mass as conversion factor) 3)calculate mole ratio (compare actual ratio to calculated ratio) 4)use the amount of limiting reactant to calculate amount of product produced 5)Calculate how much is left in excess of non-limiting reactant (if necessary).

Example: Find the limiting reactant if 78g Na2O2 were reacted with 29.4g H2O

molar mass of Na2O2= Na (22.99)*2=45.98 O(16*2)=32      45.98+32=77.98 g

molar mass of H2O= H (1*2)=2 O=16    2+16=18g

so 78g * (1mol/77.98g)=1.001 mol of Na2O2

and 29.4g * (1mol/18g)=1.633 mol of H2O

given that there are only 1.001 mols of Na2O2, it is the limiting reactant

3. In a chemical reaction, the starting materials are the reactants and the substances formed are the products. In some reactions, one reactant may be used up before the others are depleted. The substance that is used up first is the limiting reactant. In order to find out the limiting reactant you need to look at the part of chemistry that studies amounts of substances that are involved in a reaction. You might be looking at the amounts of substances before the reaction. You might be looking at the amount of material that is produced by the reaction. By finding the limited reactant it helps us achieve our goal of finding out what was left over after the reaction completed.

An example of a limiting reactant is my preparation of French toast. A recipe for French toast requires one egg, 1/2 c of milk, 2 tbsp of oil, and four pieces of bread. On a busy morning, everyone in my family wants French toast. I check my supplies to see how many pieces of French toast I can serve and I find 6 eggs, 4 c of milk, 16 tbsp of oil, and 32 pieces of bread. This tells me that I can only prepare 24 pieces of French toast, six servings, even though I have enough milk, oil, and bread to make more. In this example, the eggs represent the limiting reactant.

 

 

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Benchmark – Risk Management Program Analysis – Part Two

August 17, 2025/in General Questions /by Besttutor

The purpose of this assignment is to analyze how an organization’s quality and improvement processes contribute to its risk management program.

This assignment builds on the Risk Management Program Analysis – Part One assignment you completed in Topic 1 of this course.

Assume that the sample risk management program you analyzed in Topic 1 was implemented and is now currently in use by your health care employer/organization. Further assume that your supervisor has asked you to create a high‐level summary brief of this new risk management program to share with a group of administrative personnel from a newly created community health organization in your state who has enlisted your organization’s assistance in developing their own risk management policies and procedures.

Compose a 1,250‐1,500 word summary brief that expands upon the elements you first addressed in the Topic 1 assignment. In this summary brief, address the following points regarding your health care organization and its risk management program:

  1. Explain the role of your organization’s MIPPA-approved accreditation body (e.g., JC, ACR, IAC) in the evaluation of your institution’s quality improvement and risk management processes.
  2. Describe the roles that different levels of administrative personnel play in healthcare ethics and establishing or sustaining employer/employee-focused organizational risk management strategies and operational policies.
  3. Illustrate how your organization’s risk management and compliance programs support ethical standards, patient consent, and patient rights and responsibilities.
  4. Explain the legal and ethical responsibilities health care professionals face in upholding risk management policies and administering safe health care at your organization.
  5. Relate how your organization’s quality improvement processes support and contribute to its overall journey to excellence.

In addition to your textbook, you are required to support your analysis with a minimum of three peer‐reviewed references.

Prepare this assignment according to the guidelines found in the APA Style Guide, located in the Student Success Center. An abstract is not required.

This assignment uses a rubric. Please review the rubric prior to beginning the assignment to become familiar with the expectations for successful completion.

You are required to submit this assignment to LopesWrite. Refer to the LopesWrite Technical Support articles for assistance.

Benchmark Information

This benchmark assignment assesses the following programmatic competencies:

BS Health Sciences

3.3 Explain the ethical and legal responsibilities of health care professionals related to risk management assessment and policies.

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Geology homework help

August 16, 2025/in General Questions /by Besttutor

This discussion is to help prepare you for the ITSP, Part 2 assignment.  The concepts being discussed here relate to risk management and business continuity planning from the business perspective.  In your ITSP Part 2 assignment you will discuss these topics from an IT perspective.  Provide a response to one of the following:

  1. Referring to the ITSP, Part 2 assignment #4 and the GGFRT case study, you will identify some risks that the CIO needs to consider.  For this discussion, we will focus on risks that the business should be concerned with.  Apply what you know about the business environment and come up with and explain 3 risks related to the business environment (not IT-related risks).  Explain what impact the risk has on the business, how likely it is to occur, and how it can be prevented or mitigated.
  2. Referring to the ITSP, Part 2 assignment #5 and the GGFRT case study, regarding developing a business continuity plan for GGFRT, the first step is to identify the essential business processes that sustain ongoing operations of GGFRT.  Reviewing the case study, identify 3 essential business processes.  Explain how these processes (not systems) could continue in the event of a disaster that makes their IT systems and their current buildings unavailable.

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NEWS ARTICLE

August 16, 2025/in General Questions /by Besttutor

2 page EACH  summary of ALL 3 TOPICS. NEW ARTICLES PROVIDED SOURCES

  • Streams and ground water x2 PAGES
  • Glaciation and deserts x 2 pages
  • Seafloor provinces and sediment x2 pages

6 pages total

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Topographic Maps

August 16, 2025/in General Questions /by Besttutor

HW5:Topographic Maps

Learning Goals:

  • Explain how elevation is described on a topographic map with contour lines
  • Estimate the elevation of any point on a topographic map
  • Identify areas that are steeply sloped or gently sloped on a topographic map
  • Identify the shape of land forms on a topographic map, including whether slopes are concave-up or concave-down
  • Use the Rule of Vs on a topographic map to determine the direction a river is flowing
  • Determine the gradient of a stream or other linear feature on a topographic map
  • Use the map scale to infer distances on a topographic map
  • Identify the latitude and longitude of the corners on a topographic map
  • Describe what is meant by a “7.5 minute” topographic map
  • Describe the relationship between map scale and map detail
  • Describe how to find adjoining maps from a topographic map

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