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Home>Homework Answsers>Nursing homework helpNURSEnursingreplyPlease ensure that the Reply includes more than 200 words with scholarly articles, and the plagiarism level must remain below 20%.Understanding Person chi-square testThe Pearson chi-square test functions as a statistical tool which evaluates the existence of significant relationships between two categorical variables. The test evaluates the observed category of frequencies in data against expected frequencies when variables show independence. The chi-squared test of Pearson serves to evaluate three different types of comparisons which include goodness of fit, homogeneity, and independence. A test of goodness of fit determines whether the observed frequency distribution deviates from the theoretical distribution. The test establishes whether observed differences stem from random chance or indicate a real connection between variables. The chi-square test of independence functions as a Pearson chi-square test to evaluate whether two categorical variables show independence or relationships. The test helps establish if gender influences product preference or if handedness affects nationality. The test evaluates whether observed category frequency combinations deviate significantly from expected frequencies when variables show no relationship. (Farina, 2021)The data is arranged in a contingency table which shows the observed frequencies of each combination of categories. The testdeterminesexpected frequencies for all table cells based on the assumption that the variables are independent. The Pearson chi-square statistic (χ²) is computed through the process of dividing the squared differences between observed and expected frequencies by the expected frequencies for all cells in the table. The calculated χ² value serves todeterminethe p-value which shows the chance of finding such differences or more extreme differences when the variables are independent. The null hypothesis of independence gets rejected when the p-value falls below the typical significance level of0.05,whichindicatesa statistically significant association.(Farina, 2021)The chi-square test shows sensitivity to sample size because bigger samples tend to produce statistically significant results even when the size is small. The test does notestablishcausality; it onlyindicatesan association between variables. The test requires verification of its assumptions, which include categorical variables and expected frequencies that must be 1 or higher. The chi-square test exists in multiple forms including the chi-square test of homogeneity, so it is crucial toidentifythe test being applied.(Longe, 2022)The chi-square test functions as a statistical tool which evaluates observed data against predicted results. The main goal of this test is to establish whether observed data differences from expected data result from random chance or from actual relationships between studied variables. (Longe, 2022)The Chi-square test conclusionemergesfrom comparing the calculated Chi-square statistic to critical valuesestablishedby degrees of freedom and significance level (alpha). The null hypothesis gets rejected when the calculated Chi-square value exceeds the critical value because thisindicatesa significant difference between observed and expected frequencies. The null hypothesisremainsunchallenged when the calculated Chi-square value does not exceed the critical value.(Farina, 2021)ReferencesFarina, A. (2021).Chi-Square Test. The Gale Encyclopedia of Science. Vol 2, 6th ed.Longe, J. (2022).Chi-Square Test.The Gale Encyclopedia of Psychology. Vol 1, 4th ed.13 days ago20.06.202510Report issueBids(55)Dr. Ellen RMMISS HILLARY A+Dr. Aylin JMnicohwilliamProf Double REmily ClareDr. Sarah Blakefirstclass tutorMiss Deannasherry proffMUSYOKIONES A+Dr ClovergrA+de plusSheryl HoganPROF_ALISTERpacesetters2121ProWritingGuruIsabella HarvardBrilliant GeekWIZARD_KIMShow All Bidsother Questions(10)BUS 517/BUS517 WEEK 11 FINAL EXAM (All Correct)Applying Philosophy to Lifeanalysis for newspaper articleTheater Art EssaysCase Study DevelopmentSafety and Accident Prevention Unit 7 Essay 2ARTH E: Dean & Leibsohn on Hybridity & Its Discontents…Racism in MusicACCOUNTING ONLINE HWSophocles Oedipus Rex 1957 The Cherry Orchard 1999 Death of a Salesman (1984) Tartuffe 1983 if you watched these 3 movies i need essayse for each on of them each essay 1.5 page font 12 duble spases the essayes must consideres these 3 things 1-what does th

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